Swift Articles

This is a follow up from my previous post: The power and expressiveness of Swift ranges. For a Character Range: contain works fine let numericalRange = 1...10 numericalRange.contains(8) // true let a: Character = "a" let z: Character = "z" let alphabeticalRange = a...z alphabeticalRange.contains("k") // true for-loop and count don’t work print(numericalRange.count) // 10 print(alphabeticalRange.count) // ❌ Referencing property 'count' on 'ClosedRange' requires that 'Character' conform to 'Strideable' for num in numericalRange { print(num) // 1 2 3 4 5 6 7 8 9 10 } for char in alphabeticalRange { // ❌ Referencing instance method 'next()' on 'ClosedRange' requires that 'Character' conform to 'Strideable' print(char) } What both of those errors mean is that Swift can’t figure out what the next character is for a given character....

What problem do some and any solve? var x: Equatable = 10 // Error: Use of protocol 'Equatable' as a type must be written 'any Equatable' var y: Equatable = "10" // Same error You’s think the compiler should let the above compile, it rightfully doesn’t. The compiler can’t know if the associated type of x, matches with the associated type of y. So it just forbids it. Compiler just doesn’t want to be in situation where you’d try something like:...

Ranges in swift are super simple to create. Yet they come in various forms. let r1 = 1...3 let r2 = 1..<3 let r3 = ...3 let r4 = 3... let r5 = ..<3 They all have range like characteristics, but have slightly different traits. It’s because they’re actually different types. Different Range Types let r1 = 1...3 // ClosedRange<Int> let r2 = 1..<3 // Range<Int> let r3 = ...3 // PartialRangeThrough<Int> let r4 = 3....